7n^2-26n+15=0

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Solution for 7n^2-26n+15=0 equation: 



7n^2-26n+15=0

a = 7; b = -26; c = +15;
Δ = b2-4ac
Δ = -262-4·7·15
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-16}{2*7}=\frac{10}{14}
=5/7
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+16}{2*7}=\frac{42}{14}
=3
$

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